(x^2-81)(4x+1)=0

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Solution for (x^2-81)(4x+1)=0 equation: 


Simplifying
(x2 + -81)(4x + 1) = 0

Reorder the terms:
(-81 + x2)(4x + 1) = 0

Reorder the terms:
(-81 + x2)(1 + 4x) = 0

Multiply (-81 + x2) * (1 + 4x)
(-81(1 + 4x) + x2(1 + 4x)) = 0
((1 * -81 + 4x * -81) + x2(1 + 4x)) = 0
((-81 + -324x) + x2(1 + 4x)) = 0
(-81 + -324x + (1 * x2 + 4x * x2)) = 0
(-81 + -324x + (1x2 + 4x3)) = 0
(-81 + -324x + 1x2 + 4x3) = 0

Solving
-81 + -324x + 1x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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